How do you simplify $\frac{2 p + 3}{2 p^{2} + 7 p + 6}$ $(2p+3)/(2p^2+7p+6)$ ?

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How do you simplify $\frac{2 p + 3}{2 p^{2} + 7 p + 6}$ $(2p+3)/(2p^2+7p+6)$ ?

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Answer 1 · 2016-09-06T11:19:06

$\frac{1}{p + 2}$ $1/(p+2)$

Explanation:

$\frac{2 p + 3}{2 p^{2} + 7 p + 6} = \frac{2 p + 3}{2 p^{2} + 4 p + 3 p + 6} = \frac{2 p + 3}{2 p (p + 2) + 3 (p + 2)}$ $(2p+3)/(2p^2+7p+6)=(2p+3)/(2p^2+4p+3p+6)=(2p+3)/(2p(p+2)+3(p+2)$ = $cancel((2p+3))/(cancel((2p+3))(p+2))$ = $1/(p+2)$ [Ans]

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How do you simplify $\frac{2 p + 3}{2 p^{2} + 7 p + 6}$ $(2p+3)/(2p^2+7p+6)$ ?

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How do you simplify $\frac{2 p + 3}{2 p^{2} + 7 p + 6}$ $(2p+3)/(2p^2+7p+6)$ ?