How do you simplify #(2x - 3)/(x + 1) + (6x + 5)/(x + 1)#?

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Answer 1 · 2018-04-04T15:01:43

#(8x+2)/(x+1)#

Add the numerators

When adding fractions, the denominators have to be the same

Here, both denominators are #x+1#, so the numerators can be added together without having to find a common denominator for both

#(2x-3+(6x+5))/(x+1)#

#(2x-3+6x+5)/(x+1) rarr# Combine like terms

#(2x+6x-3+5)/(x+1)#

#(8x+2)/(x+1)#