How do you simplify $(2x+7)/(x^2-y^2)+(-5)/(x^2-2xy+y^2)$ ?

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Answer 1 · 2018-05-26T08:23:08

see below

$(2x+7)/(x^2-y^2)+ (-5)/(x^2-2xy+y^2)$

firstly factorise the denominators

$(2x+7)/((x+y)(x-y))-5/(x-y)^2$

we need the denominators the same

multiply top /bottom of first fraction by $(x-y)$

multiply top/bottom of second fraction by $(x+y)$

$((2x+7)(x-y))/((x+y)(x-y)^2)-(5(x+y))/((x+y)(x-y)^2)$

now simplify

$(2x^2-2xy+7x-7y-5x-5y)/((x+y)(x-y)^2)$

$(2x^2-2xy+2x-12y)/((x+y)(x-y)^2)$

$(2(x^2-xy+x-6y))/((x+y)(x-y)^2)$

How do you simplify (2x+7)/(x^2-y^2)+(-5)/(x^2-2xy+y^2)(2x+7)/(x^2-y^2)+(-5)/(x^2-2xy+y^2)?