How do you simplify $2 x + 7 y - 8 (5 x - 2 y)$ $2x + 7y - 8( 5x - 2y )$ ?

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Answer 1 · 2018-05-23T03:42:08

$- 38 x + 23 y$ $-38x+23y$

We can start by distributing the $- 8$ $-8$ to both terms in the parenthesis. Doing this, we get

$2 x + 7 y - 40 x + 16 y$ $2x+7y-40x+16y$

Now, we just look for like terms. The $x$ $x$ terms go with each other, and so do the $y$ $y$ terms. We get

$- 38 x + 23 y$ $-38x+23y$

Hope this helps!

Answer 2 · 2018-05-23T03:46:04

$23 y - 38 x$ $23y-38x$

We start with applying BODMAS rule, which clearly tells that the terms with brackets should be simplified first. Hence consider:

$- 8 x (5 x - 2 y)$ $-8x(5x-2y)$

$= [(- 8 x \cdot 5 y) + (- 8 x \cdot - 2 y)]$ $= [(-8x*5y)+(-8x*-2y)]$

$= [(- 40 x) + (+ 16 y)]$ $= [(-40x)+(+16y)]$

$= - 40 x + 16 y$ $= -40x+16y$

Now consider the whole question and plug in the simplified value
We get,

$2 x + 7 y - 40 x + 16 y$ $2x+7y-40x+16y$

Now add or subtract the coefficients of the same variables depending on the sign they carry. We get:

$2 x - 40 x + 7 y + 16 y = - 38 x + 23 y$ $2x-40x +7y+16y = -38x+23y$

You can leave it at this or just put the term with '+' at the first as I have.

Hope it helped! All the best

How do you simplify 2x + 7y - 8( 5x - 2y )2x+7y−8(5x−2y)2x + 7y - 8( 5x - 2y )?