How do you simplify $3 (15 x - 9 y) + 5 (4 y - x)$ $3(15x-9y)+5(4y-x)$ ?

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Answer 1 · 2017-05-13T01:52:19

$40 x - 7 y$ $40x-7y$

Begin by distributing the $3$ $3$ to $15 x - 9$ $15x-9$ and distributing the $5$ $5$ to $4 y - x$ $4y-x$

$3 (15 x - 9 y) + 5 (4 y - x) \to 45 x - 27 y + 20 y - 5 x$ $3(15x-9y)+5(4y-x) -> 45x-27y+20y-5x$

Simplify by combing like terms:

$45 x - 27 y + 20 y - 5 x$ $color(blue)(45x)color(red)(-27y)color(red)(+20y)color(blue)(-5x)$

This results in our final answer:

$40 x - 7 y$ $40x-7y$

How do you simplify 3(15x-9y)+5(4y-x)3(15x−9y)+5(4y−x)3(15x-9y)+5(4y-x)?