How do you simplify $(-3-4i)^2$ ?

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Answer 1 · 2016-09-18T16:11:41

$-7+24i$

$(-3-4i)^2$

To square a binomial, rewrite the problem as the binomial multiplied by the binomial. Do NOT distribute the exponent!
$(-3-4i)(-3-4i)$

Distribute (FOIL)
$9+12i+12i+16i^2$

Combine like terms. $i^2=-1$
$9+24i+16*-1$

$9+24i-16$

$-7+24i$

How do you simplify (-3-4i)^2(-3-4i)^2?