How do you simplify $(3 - 8 i) - (5 + 2 i)$ $(3-8i)-(5+2i)$ ?

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How do you simplify $(3 - 8 i) - (5 + 2 i)$ $(3-8i)-(5+2i)$ ?

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Answer 1 · 2016-07-27T09:05:34

$(- 2 - 10 i)$ $(-2-10i)$

Explanation:

General solution

Let the real component by $R$ $R$
Let the imaginary component be $I m$ $Im$

Then $(R_{1} + I m_{1}) - (R_{2} + I m_{2}) = [R_{1} - R_{2}] + [I m_{1} - I m_{2}]$ $(R_1+Im_1)-(R_2+Im_2) = [R_1-R_2]+[Im_1-Im_2]$
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Thus we have:

$[3 - 5] + [- 8 i - 2 i] = (- 2 - 10 i)$ $[3-5]+[-8i-2i]" "=" "color(blue)((-2-10i))$

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It is just like algebra!

$(3 - 8 i) - (5 + 2 i) 3 - 8 i - 5 - 2 i$ $(3-8i)-(5+2i)" "3-8i-5-2i$

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How do you simplify $(3 - 8 i) - (5 + 2 i)$ $(3-8i)-(5+2i)$ ?

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How do you simplify $(3 - 8 i) - (5 + 2 i)$ $(3-8i)-(5+2i)$ ?