How do you simplify $3/(w + 4) + 8/(3w) + 12/(w(w +4))$ ?

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Answer 1 · 2017-05-23T07:18:08

$3/(w+4)+8/(3w)+12/(w(w+4))=17/(3w)$

In $3/(w+4)+8/(3w)+12/(w(w+4))$ , we have denominators as

$w+4$ , $3w$ and $w(w+4)$ , whose LCD is $3w(w+4)$

so convertig all to common denomiator, we get

$3/(w+4)=3/(w+4)xx(3w)/(3w)=(9w)/(3w(w+4)$

$8/(3w)=8/(3w)xx(w+4)/(w+4)=(8w+32)/(3w(w+4)$ and

$12/(w(w+4))=12/(w(w+4))xx3/3=36/(3w(w+4)$

Hence, $3/(w+4)+8/(3w)+12/(w(w+4))$

= $(9w+8w+32+36)/(3w(w+4)$

= $(17w+68)/(3w(w+4)$

= $(17(w+4))/(3w(w+4))$

= $(17cancel((w+4)))/(3wcancel((w+4)))$

= $17/(3w)$

How do you simplify 3/(w + 4) + 8/(3w) + 12/(w(w +4))3/(w + 4) + 8/(3w) + 12/(w(w +4))?