How do you simplify #(-3r^2s^-4)(2r^-3s^7)^2#?

1 Answer
sankarankalyanam
Jun 20, 2018

#color(indigo)(=> -12 r^-4 * s^10 = (-12 s^10)/r^4#

Explanation:

![http://quantbasics.blogspot.com/2010/04/http://indices-and-surds.html](https://useruploads.socratic.org/AAJCnfJYRLOF0YhMuGcR_theory%20of%20indices.jpg)

#(-3 r^2 s^-4)((2r^-3s^7)^2#

#=> (-3 r^2 s^-4) (2^2 r^-6 s^14)#

#=> (-3 * 4 * r^2 * r^-6 * s^-4 * s^14)#

#color(indigo)(=> -12 r^-4 * s^10 = (-12 s^10)/r^4#

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