How do you simplify $(3w^2-12)/(w^2+5w+6)$ ?

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Answer 1 · 2016-09-20T02:36:26

We must factor both the numerator and the denominator.

$=(3(w^2 - 4))/((w + 3)(w + 2))$

$= (3(w + 2)(w - 2))/((w + 3)(w + 2))$

$=(3(w - 2))/(w +3)$

Finally, let's note the restrictions on the variable. We cannot have the denominator equal 0, so $w !=3 and -2$ .

Hopefully this helps!

How do you simplify (3w^2-12)/(w^2+5w+6)(3w^2-12)/(w^2+5w+6)?