How do you simplify 3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 ? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 1, 2016 3x^(2/3)y^(3/4)(2x^(5/3)y^(1/2))^3=24x^(13/3)y^(9/4) Explanation: 3x^(2/3)y^(3/4)(2x^(5/3)y^(1/2))^3 = 3x^(2/3)y^(3/4)(2^3(x^(5/3))^3(y^(1/2))^3) = 3x^(2/3)y^(3/4)*8(x^(5/3xx3))(y^(1/2xx3)) = 24x^(2/3)y^(3/4)(x^5)(y^(3/2)) = 24x^(2/3+5)y^(3/4+3/2) = 24x^(13/3)y^(9/4) Answer link Related questions How do you simplify c^3v^9c^-1c^0? How do you simplify (- 1/5)^-2 + (-2)^-2? How do you simplify (4^6)^2 ? How do you simplify 4^3·4^5? How do you simplify (5^-2)^-3? How do you simplify and write (-5.3)^0 with positive exponents? How do you factor 12j^2k - 36j^6k^6 + 12j^2? How do you simplify the expression 2^5/(2^3 times 2^8)? When can I add exponents? What is the Zero Exponent Rule? See all questions in Exponents Impact of this question 3780 views around the world You can reuse this answer Creative Commons License