How do you simplify 3x23y34(2x53y12)3? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 1, 2016 3x23y34(2x53y12)3=24x133y94 Explanation: 3x23y34(2x53y12)3 = 3x23y34(23(x53)3(y12)3) = 3x23y34⋅8(x53×3)(y12×3) = 24x23y34(x5)(y32) = 24x23+5y34+32 = 24x133y94 Answer link Related questions How do you simplify c3v9c−1c0? How do you simplify (−15)−2+(−2)−2? How do you simplify (46)2? How do you simplify 43⋅45? How do you simplify (5−2)−3? How do you simplify and write (−5.3)0 with positive exponents? How do you factor 12j2k−36j6k6+12j2? How do you simplify the expression 2523×28? When can I add exponents? What is the Zero Exponent Rule? See all questions in Exponents Impact of this question 3827 views around the world You can reuse this answer Creative Commons License