How do you simplify the expression $\frac{2^{5}}{2^{3} \times 2^{8}}$ $2^5/(2^3 times 2^8)$ ?

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Answer 1 · 2016-06-21T06:43:25

$\frac{2^{5}}{2^{3} \times 2^{8}} = \frac{1}{2^{6}}$ $2^5/(2^3xx2^8)=1/2^6$

$\frac{2^{5}}{2^{3} \times 2^{8}}$ $2^5/(2^3xx2^8)$

= $\frac{2^{5}}{2^{3} \times 2^{3 + 5}}$ $2^5/(2^3xx2^(3+5))$

= $\frac{2^{5}}{2^{3} \times 2^{3} \times 2^{5}}$ $2^5/(2^3xx2^3xx2^5)$

= $(1cancel2^5)/(2^3xx2^3xxcancel2^5)$

= $1/(2^3xx2^3)=1/2^(3+3)=1/2^6$

How do you simplify the expression 2^5/(2^3 times 2^8)2523×282^5/(2^3 times 2^8)?