Question

How do you simplify `(3x^2+6y)/(3x^2+9x)`?

Answer 1

`(x^2 + 2y)/(x*(x + 3)`

Explanation:

`(3x^2 +6y)/(3x^2 +9x)`

Factor out 3 from numerator, and 3x from the denominator:
`=(3*x^2 + (3*2)y)/(3x*x + 3*3x)`
`=(3*(x^2 + 2y))/(3x*(x + 3))`

Then cancel out the 3 from the numerator and the denominator:
`=(cancel 3*(x^2 + 2y))/(cancel 3 x*(x + 3))`

So you have:
`=(x^2 + 2y)/(x*(x + 3)`