How do you simplify $(4 - 3 i) (2 + 5 i)$ $(4-3i)(2+5i)$ and write in a+bi form?

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How do you simplify $(4 - 3 i) (2 + 5 i)$ $(4-3i)(2+5i)$ and write in a+bi form?

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Answer 1 · 2018-04-21T18:17:54

$23 + 14 i$ $23+14i$

Explanation:

$∙ x i^{2} = {(\sqrt{- 1})}^{2} = - 1$ $•color(white)(x)i^2=(sqrt(-1))^2=-1$

$expand factors using FOIL$ $"expand factors using FOIL"$

$\Rightarrow 8 + 20 i - 6 i - 15 i^{2}$ $rArr8+20i-6i-15i^2$

$= 23 + 14 i \leftarrow in standard form$ $=23+14ilarrcolor(blue)"in standard form"$

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How do you simplify $(4 - 3 i) (2 + 5 i)$ $(4-3i)(2+5i)$ and write in a+bi form?

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How do you simplify (4−3i)(2+5i)(4-3i)(2+5i) and write in a+bi form?

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How do you simplify $(4 - 3 i) (2 + 5 i)$ $(4-3i)(2+5i)$ and write in a+bi form?