Question

How do you simplify `(4-6i)/i`?

Answer 1

`(4-6i)/i=(2(2-3i))/i=2(2/i-3i/i)=2(2/ixxi/i-3)`
`=2((2i)/i^2-3)=2((2i)/-1-3)=-2(2i+3), or, -2(3+2i)`.