How do you simplify $- 4 d + 2 (3 + d)$ $-4d+2 (3+d)$ ?

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Answer 1 · 2018-04-07T05:30:14

$- 2 d + 6$ $-2d + 6$

Here's how I did it:

First, we have to distribute/expand out $2 (3 + d)$ $2(3+d)$ :

$2 \cdot 3 = 6$ $2 * 3 = 6$

$2 \cdot d = 2 d$ $2 * d = 2d$

Now we put this back into the expression:
$- 4 d + 6 + 2 d$ $-4d + 6 + 2d$

We can still simplify this since $- 4 d$ $-4d$ and $2 d$ $2d$ are like terms:
$- 2 d + 6$ $-2d + 6$

Hope this helps!

How do you simplify −4d+2(3+d)-4d+2 (3+d)?