How do you simplify #(4i)(2i)+3#?
1 Answer
Aug 30, 2016
Explanation:
The first step is to multiply the 2 values.
#rArr(4i)(2i)=8i^2#
#color(orange)"Reminder " color(red)(|bar(ul(color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr(4i)(2i)+3=8i^2+3=-8+3=-5#
