How do you simplify #(-5 - 3i)/(4i)#?

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Answer 1 · 2018-06-30T23:32:32

#-3/4+5/4i#

The convention is to not have irrational numbers in the denominator, so let's multiply the top and bottom by #4i#.

#(4i(-5-3i))/(4i*4i)#

#=(-20i-12i^2)/(16i^2)#

Recall that #i^2=-1#. This now simplifies to

#(-20i+12)/-16#

We can factor out a #4# in all terms to get

#(-5i+3)/-4#

This simplifies to

#-3/4+5/4i#

Hope this helps!