How do you simplify $\frac{5}{x - 3} + \frac{x}{x^{2} - 9}$ $(5)/(x-3) + (x)/(x^2-9)$ ?

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How do you simplify $\frac{5}{x - 3} + \frac{x}{x^{2} - 9}$ $(5)/(x-3) + (x)/(x^2-9)$ ?

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Answer 1 · 2016-05-13T10:08:58

$\frac{6 x + 15}{x^{2} - 9}$ $(6x+15)/(x^2-9)$

Explanation:

$(x^{2} - 9) = (x + 3) (x - 3)$ $(x^2-9)=(x+3)(x-3)$ and $\frac{5}{x - 3} = 5 \frac{x + 3}{(x - 3) (x + 3)} = \frac{5 x + 15}{x^{2} - 9}$ $5/(x-3)=5(x+3)/((x-3)(x+3)) =(5x+15)/(x^2-9)$
so $\frac{5}{x - 3} + \frac{x}{x^{2} - 9} = \frac{5 x + 15}{x^{2} - 9} + \frac{x}{x^{2} - 9} = \frac{6 x + 15}{x^{2} - 9}$ $5/(x-3)+x/(x^2-9) = (5x+15)/(x^2-9)+x/(x^2-9) = (6x+15)/(x^2-9)$

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How do you simplify $\frac{5}{x - 3} + \frac{x}{x^{2} - 9}$ $(5)/(x-3) + (x)/(x^2-9)$ ?

1 Answer

Explanation:

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