How do you simplify 5sqrt(-25) • i525i?

1 Answer
Nov 14, 2015

-2525

Explanation:

5sqrt(-25)*i = 5isqrt(25)*i = 5i*5i = 25*i^2 = -25525i=5i25i=5i5i=25i2=25

In common with all non-zero numbers, -2525 has two square roots.

The square root represented by the symbols sqrt(-25)25 is the principal square root i sqrt(25) = 5ii25=5i. The other square root is -sqrt(-25) = -i sqrt(25) = -5i25=i25=5i.

When a, b >= 0a,b0 then sqrt(ab) = sqrt(a)sqrt(b)ab=ab, but that fails if both a < 0a<0 and b < 0b<0 as in this example:

1 = sqrt(1) = sqrt(-1 * -1) != sqrt(-1)*sqrt(-1) = -11=1=1111=1