Question

How do you simplify `(6-2i)(1+i)`?

Answer 1

You work out the multiplication using FOIL:

Explanation:

`=6*1+(-2i)*1+6*i+(-2i)*i`

`=6-2i+6i-2i^2`

Since `i^2=-1`:

`=6-2i+6i+2`

`=8+4i`