Question

How do you simplify `(6 + 4i )(3 + 2i )`?

Answer 1

Answer is `10+24i` and process is detailed below.

Explanation:

These are two complex numbers. These are of the form `a+bi` where `a` and `b` are real and `i` is an imaginary number so that `i^2=-1`. Hence in `a+bi`, `a` is called real part and `bi` imaginary part,

Now multiplying `(6+4i)(3+2i)` gives us

`18+12i+12i+8i^2` and as `i^2=-1`, this becomes

`18+12i+12i-8` or `10+24i`