How do you simplify #(6-isqrt2)/(6+isqrt2)# and write the complex number in standard form?
1 Answer
Nov 6, 2016
Please see the explanation for steps leading to the answer:
Explanation:
Multiply the numerator and denominator by the complex conjugate of the denominator,
This done, because it is well known that this will turn the denominator into a real number:
Substitute -1 for
Use the pattern
Substitute -1 for