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How do you simplify $64^{π} \div 2^{π}$ $64^pidiv2^pi$ ?

1 Answer

Shwetank Mauria

Oct 10, 2016

$64^{π} \div 2^{π} = 32^{π}$ $64^pi-:2^pi=32^pi$

Explanation:

$64^{π} \div 2^{π}$ $64^pi-:2^pi$

= ${(\frac{64}{2})}^{π}$ $(64/2)^pi$

= $32^{π}$ $32^pi$

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