How do you simplify #6i*-4i+8#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer LM Dec 26, 2016 #48i + 24# Explanation: multiply each number separately: #6i * -4i = -24 * i^2 = -24 * -1# #= 24# #6i * 8 = 48 * i# #= 48i# add the two products: #24 + 48 i = 48i + 24# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 2110 views around the world You can reuse this answer Creative Commons License