Do not like decimals so lets get rid of them.
Multiply everything by 1 but in the form of #color(red)(1=10/10)#
If we do the division by 10 at the end we would have the correct answer.
Note: Using an example suppose we had #10(a+b)#. This is the same as #10a+10b#
So using the above principle:
#color(green)(color(red)(10/10)[color(white)(2/2)7(0.2p+0.3q)+5(0.6p-q)color(white)(2/2)]#
#color(green)(color(red)(1/10)[color(white)(2/2)color(white)("b")7(2p+3q)color(white)("bb")+5(6p-10q)color(white)(2/2)]#
#color(green)(color(red)(1/10)[color(white)(2/2)14p+21q+30p-50qcolor(white)(2/2)]#
#color(green)(color(red)(1/10)[color(white)(2/2)44p-29qcolor(white)(2/2)]#
#color(white)("bbbbb")color(green)(4.4p-2.9q)#