How do you simplify $7 + 2 (4 x - 3)$ $7+2 (4x - 3)$ ?

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How do you simplify $7 + 2 (4 x - 3)$ $7+2 (4x - 3)$ ?

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Answer 1 · 2015-07-08T16:01:38

$8 x + 1$ $8x+1$

Explanation:

Multiply out the terms and add similar terms:-
$7 + 2 (4 x - 3) = 7 + 8 x - 6 = 8 x + 1$ $7+2(4x-3)=7+8x-6=8x+1$

Answer 2 · 2015-07-08T16:02:55

$7 + 2 (4 x - 3) = 1 + 8 x$ $7+2(4x-3) = 1+8x$

Explanation:

$7 + 2 (4 x - 3)$ $7+2(4x-3)$
distributing the $2$ $2$ over the terms of $(4 x - 3)$ $(4x-3)$
$XXXX$ $color(white)("XXXX")$ $= 7 + (2) (4 x) - (2) (3)$ $=7+(2)(4x) -(2)(3)$
performing the multiplication
$XXXX$ $color(white)("XXXX")$ $= 7 + 8 x - 6$ $= 7 +8x - 6$
grouping like terms
$XXXX$ $color(white)("XXXX")$ $= (7 - 6) + (8 x)$ $=(7-6) + (8x)$
performing the subtraction
$XXXX$ $color(white)("XXXX")$ $= 1 + 8 x$ $=1 + 8x$

Answer 3 · 2015-07-08T16:23:17

Distribute the $2$ $2$ , then simplify.

Explanation:

$7 + 2 (4 x - 3)$ $7+2(4x-3)$

Distribute the $2$ $2$ .

$7 + 2 \cdot 4 x + 2 \cdot - 3$ $7+2*4x+2*-3$ =

Simplify.

$7 + 8 x - 6$ $7+8x-6$ =

$8 x + 1$ $8x+1$

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How do you simplify $7 + 2 (4 x - 3)$ $7+2 (4x - 3)$ ?

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How do you simplify $7 + 2 (4 x - 3)$ $7+2 (4x - 3)$ ?