How do you simplify $7^{\sqrt{2}} \cdot 7^{3 \sqrt{2}}$ $7^sqrt2*7^(3sqrt2)$ ?

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Answer 1 · 2018-07-28T12:18:19

$7^{4 \sqrt{2}}$ $7^{4\sqrt2}$

Powers on the same base, are added in the multiplication as follows

$7^{\sqrt{2}} \cdot 7^{3 \sqrt{2}}$ $7^{\sqrt2}\cdot 7^{3\sqrt2}$

$= 7^{\sqrt{2} + 3 \sqrt{2}}$ $=7^{\sqrt2+3\sqrt2}$

$= 7^{4 \sqrt{2}}$ $=7^{4\sqrt2}$

How do you simplify 7√2⋅73√27^sqrt2*7^(3sqrt2)?