How do you simplify #(8-4i)(6+3i)#?
1 Answer
Sep 14, 2016
60
Explanation:
distribute the brackets using, for example, the FOIL method.
#rArr(8-4i)(6+3i)=48+24i-24i-12i^2=48-12i^2#
#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(i^2=(sqrt(-1))^2=-1)color(white)(a/a)|)))#
#rArr48-12i^2=48+12=60# Thus
#(8-4i)(6+3i)=60#
