How do you simplify ${(b^{\sqrt{6}})}^{\sqrt{24}}$ $(b^sqrt6)^sqrt24$ ?

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How do you simplify ${(b^{\sqrt{6}})}^{\sqrt{24}}$ $(b^sqrt6)^sqrt24$ ?

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Answer 1 · 2018-04-17T06:52:00

$b^{12}$ $b^12$ is the answer

Explanation:

We have, ${(b^{\sqrt{6}})}^{\sqrt{24}}$ $(b^sqrt(6))^sqrt(24)$
On further simplification,it comes out to be,
$b^{\sqrt{6 \times 24}}$ $b^(sqrt(6xx24))$ , or, $b^{\sqrt{144}}$ $b^(sqrt(144))$
Which comes out to be $b^{12}$ $b^12$

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How do you simplify ${(b^{\sqrt{6}})}^{\sqrt{24}}$ $(b^sqrt6)^sqrt24$ ?

1 Answer

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Math

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How do you simplify (b√6)√24(b^sqrt6)^sqrt24?

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Explanation:

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How do you simplify ${(b^{\sqrt{6}})}^{\sqrt{24}}$ $(b^sqrt6)^sqrt24$ ?