How do you simplify $f (θ) = cot 4 θ - sin 8 θ - 2 tan 2 θ$ $f(theta)=cot4theta-sin8theta-2tan2theta$ to trigonometric functions of a unit $θ$ $theta$ ?

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How do you simplify $f (θ) = cot 4 θ - sin 8 θ - 2 tan 2 θ$ $f(theta)=cot4theta-sin8theta-2tan2theta$ to trigonometric functions of a unit $θ$ $theta$ ?

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Answer 1 · 2017-08-14T02:48:25

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Explanation:

$f (θ) = cot 4 θ - sin 8 θ - 2 tan 2 θ \equiv \frac{cos 4 θ}{sin 4 θ} - 2 sin 4 θ cos 4 θ - \frac{4 tan θ}{1 - {tan}^{2} θ}$ $f(theta) = cot4theta - sin8theta - 2tan2theta -= (cos4theta)/(sin4theta) - 2sin4thetacos4theta - (4tantheta)/(1-tan^2theta)$

Exercise:

Finish writing $f (θ)$ $f(theta)$ in terms of a unit $θ$ $theta$ using the expansions of $sin 4 θ$ $sin4theta$ and $cos 4 θ$ $cos4theta$ given here: https://socratic.org/questions/how-do-you-simplify-f-theta-sec4theta-tan4theta-to-trigonometric-functions-of-a-#463667

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How do you simplify $f (θ) = cot 4 θ - sin 8 θ - 2 tan 2 θ$ $f(theta)=cot4theta-sin8theta-2tan2theta$ to trigonometric functions of a unit $θ$ $theta$ ?

1 Answer

Explanation:

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How do you simplify f(theta)=cot4theta-sin8theta-2tan2thetaf(θ)=cot4θ−sin8θ−2tan2θf(theta)=cot4theta-sin8theta-2tan2theta to trigonometric functions of a unit thetaθtheta?

1 Answer

Explanation:

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How do you simplify $f (θ) = cot 4 θ - sin 8 θ - 2 tan 2 θ$ $f(theta)=cot4theta-sin8theta-2tan2theta$ to trigonometric functions of a unit $θ$ $theta$ ?