How do you simplify #\frac { 3a } { 2a b } - \frac { 2a } { 4}#?

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Answer 1 · 2017-08-23T18:27:49

#(a(3 - ab))/(2b)#

First, you make a common denominator.

#(3a)/(2ab) - (2a)/4 = (3a)/(2ab) - (2*a^2*b)/(4ab)#

Next, you multiply the fraction #(3a)/(2ab)# in the numerator and denominator by #2#. Then you get

#(6a)/(4ab)#

Now you do

#(6a)/(4ab) - (2 * a^2 * b)/(4ab) = (2a(3-ab))/(4b) = (a(3 - ab))/(2b)#

Sorry for making it so complicated.