How do you simplify ${log}_{9} 7 x + {log}_{9} x + {log}_{9} 5 x$ $log_9 7x + log_9 x + log_9 5x$ ?

Question

1930 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-07-26T20:51:38

${log}_{9} 35 x^{3}$ $log_9 35x^3$

Note that ${log}_{k} a + {log}_{k} b = {log}_{k} a b$ $log_ka+log_kb=log_kab$ , we therefore have:

${log}_{97} x + {log}_{9} x + {log}_{95} x = {log}_{9} 35 x^{3}$ $log_97x+log_9x+log_95x=log_9 35x^3$

How do you simplify log_9 7x + log_9 x + log_9 5xlog97x+log9x+log95xlog_9 7x + log_9 x + log_9 5x?