How do you simplify $((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$ ?

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Answer 1 · 2017-04-15T20:01:02

$((2p-1)^2)/((p+1))$

This is just a question of knowing your indice laws.

$((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)$

When there is a division of indices with the same base, the indices are subtracted.

For $(p+1)$ , it is $1-2 = -1$ , therefore the (p+1) on the numerator disappears and the one on the denominator stays.

$((2p-1)^4)/((p+1)(2p-1)^2)$

For $(2p-1)$ , it is $4-2=2$ , therefore the $(2p-1)$ on the denominator disappears and the one on the numerator stays.

$((2p-1)^2)/((p+1))$

How do you simplify ((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)((p+1)(2p-1)^4)/((p+1)^2(2p-1)^2)?