How do you simplify $\frac{r {(r - 3)}^{5}}{r^{3} {(r - 3)}^{2}}$ $(r(r-3)^5)/(r^3(r-3)^2)$ ?

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Answer 1 · 2016-07-22T06:34:29

$\frac{{(r - 3)}^{3}}{r^{2}}$ $(r-3)^3/r^2$

Since $\frac{a^{m}}{a^{n}} = a^{m - n}$ $a^m/a^n=a^(m-n)$ , you can have:

$\frac{r {(r - 3)}^{5}}{r^{3} {(r - 3)}^{2}} = \frac{{(r - 3)}^{5 - 2}}{r^{3 - 1}}$ $(r(r-3)^5)/(r^3(r-3)^2)=((r-3)^(5-2))/r^(3-1)$

$\frac{{(r - 3)}^{3}}{r^{2}}$ $(r-3)^3/r^2$

How do you simplify r(r−3)5r3(r−3)2(r(r-3)^5)/(r^3(r-3)^2)?