How do you simplify #(sec x / sin x) - (sin x / cos x)#?

Question

↳Redirected from "How does the rate of reaction change with concentration?"

10562 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-21T19:01:59

#cot x#

#(sec x / sin x) - (sin x / cos x)#

create common denominator

# = (sec x cos x - sin^2 x ) / (sin x cos x)#

# = (1 - sin^2 x ) / (sin x cos x)#

# = (cos^2 x ) / (sin x cos x)#

# = (cos x ) / (sin x )#

# = cot x#