How do you simplify #sqrt(-64)/-sqrt4#?

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Answer 1 · 2015-11-05T14:28:02

#sqrt(-64)/-sqrt4=-4i#

#[1]" "sqrt(-64)/-sqrt4#

Factor out the numbers inside the radical symbols.

#[2]" "=sqrt(-8^2)/-sqrt(2^2)#

Take the perfect squares out of the radical symbols.

#[3]" "=(8sqrt(-1))/-2#

The square root of #-1# is equivalent to the imaginary unit #i#.

#[4]" "=(8i)/-2#

Simplify by dividing #8i# by #-2#.

#[5]" "=color(blue)(-4i)#