How do you simplify $\frac{t^{2} - 5 t - 6}{t^{2} - 7 t + 6}$ $(t^2-5t-6)/(t^2-7t+6)$ ?

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Answer 1 · 2018-03-26T11:54:23

$\frac{t + 1}{t - 6}$ $(t+1)/(t-6)$

You have to factorize the top and bottom look for a factor that multiples into -6 and adds into -5

The possible factors are 6,1 and 3,2. We know that -6 and +1 add to -5 and multiply -6. Likewise the factors -6 and -1 add to -7 and multiply to 6.

$\frac{(t - 6) (t + 1)}{(t - 6) (t - 1)}$ $((t-6)(t+1))/((t-6)(t-1)$

can remove the common factor of $(t - 6)$ $(t-6)$ from denominator and numerator to get

$\frac{t + 1}{t - 6}$ $(t+1)/(t-6)$

How do you simplify (t^2-5t-6)/(t^2-7t+6)t2−5t−6t2−7t+6(t^2-5t-6)/(t^2-7t+6)?