Question

How do you simplify `tan^2y/secydiv(3tan^3y)/secy`?

Answer 1

`(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3`

Explanation:

Remember that when dividing fractions, it's the same as multiplying by the inverse. And so this:

`(tan^2y/secy)-:((3tan^3y)/secy)` becomes

`(tan^2y/secy)xx((secy)/(3tan^3y))`

cancel out terms to get

`(tan^2y/secy)xx((secy)/(3tan^3y))=1/(3tany)=coty/3`