How do you simplify the algebraic expression $- a (2 b - 3 c) - 3 a (b + c)$ $-a(2b - 3c) - 3a(b + c)$ ?

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How do you simplify the algebraic expression $- a (2 b - 3 c) - 3 a (b + c)$ $-a(2b - 3c) - 3a(b + c)$ ?

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Answer 1 · 2015-04-12T16:37:18

$- 5 a b$ $-5ab$

To simplify distribute $- a$ $-a$ over $2 b$ $2b$ and $3 c$ $3c$ and $- 3 a$ $-3a$ over $b$ $b$ and $c$ $c$ . It would become $- 2 a b + 3 a c - 3 a b - 3 a c .$ $-2ab+3ac -3ab -3ac.$ $+ 3 a c$ $+3ac$ and $- 3 a c$ $-3ac$ would get cancelled leaving $- 2 a b - 3 a b = - 5 a b$ $-2ab -3ab = -5ab$

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How do you simplify the algebraic expression $- a (2 b - 3 c) - 3 a (b + c)$ $-a(2b - 3c) - 3a(b + c)$ ?

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How do you simplify the algebraic expression −a(2b−3c)−3a(b+c)-a(2b - 3c) - 3a(b + c)?

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How do you simplify the algebraic expression $- a (2 b - 3 c) - 3 a (b + c)$ $-a(2b - 3c) - 3a(b + c)$ ?