How do you simplify the expression $25 {sin}^{2} x - 9$ $25sin^2x-9$ ?

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Answer 1 · 2016-11-08T20:09:34

$25 {sin}^{2} x - 9 = (5 sin x + 3) (5 sin x - 3)$ $25sin^2x-9=(5sinx+3)(5sinx-3)$

The simplest way is to use the difference of squares relation.

$a^{2} - b^{2} = (a + b) (a - b)$ $color(blue)(a^2-b^2=(a+b)(a-b))$

$25 {sin}^{2} x - 9 = (5 sin x + 3) (5 sin x - 3)$ $25sin^2x-9=(5sinx+3)(5sinx-3)$

How do you simplify the expression 25sin2x−925sin^2x-9?