How do you simplify the expression #sectheta-sinthetatantheta#?

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Answer 1 · 2016-10-29T13:26:15

The expression #=costheta#

#sectheta-sinthetatantheta=1/costheta-(sinthetasintheta)/costheta#

#=(1-sin^2theta)/costheta# but #(sin^2theta+cos^2theta=1)#

so finally we get #=cos^2theta/costheta=costheta#

Answer 2 · 2016-10-29T13:31:44

#=costheta#

#=(1/costheta) -sin^2theta/costheta#

#=(1-sin^2theta)/costheta#

#=(cos^2theta)/costheta#

#=costheta#