How do you simplify the expression #secthetacottheta#?

1 Answer
Sep 10, 2016

#csctheta#

Explanation:

Using the #color(blue)"trigonometric identities"#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(sectheta=1/(costheta)" and " cottheta=(costheta)/(sintheta))color(white)(a/a)|)))#

#rArrsecthetacottheta=1/(cancel(costheta))xxcancel(costheta)/sintheta=1/(sintheta)#

#color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(csctheta=1/(sintheta))color(white)(a/a)|)))#

#rArr1/(sintheta)=csctheta#

Thus: #secthetacottheta=csctheta#