How do you simplify the expression #tan^2xcsc^2x-tan^2x#?

Question

3711 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-13T02:20:46

The expression simplifies to #1#.

#=tan^2x(csc^2x - 1)#

#=sin^2x/cos^2x(1/sin^2x - 1)#

#= 1/cos^2x - sin^2x/cos^2x#

#=(1 - sin^2x)/cos^2x#

#=cos^2x/cos^2x#

#= 1#

Hopefully this helps!