How do you simplify using the half angle formula #sin(22^o 30')#?

1 Answer
Apr 1, 2017

#(sqrt(2-sqrt2))/2#

Explanation:

Using the #color(blue)"half angle formula for sin"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(sin(theta/2)=+-sqrt((1-costheta)/2))color(white)(2/2)|)))#

#"here "theta/2=22.5^@rArrtheta=45^@#

We only require the positive root since #22.5^@# is in the first quadrant where sine is positive.

#rArrsin(22.5^@)=sqrt((1-cos45^@)/2)#

#color(white)(XXXXXXX)=sqrt((1-1/sqrt2)/2)#

#color(white)(XXXXXXX)=sqrt((sqrt2-1)/(2sqrt2))#

#color(white)(xxxxxxxxx)=sqrt((2-sqrt2)/4#

#color(white)(xxxxxxxxx)=sqrt(2-sqrt2)/2#