How do you simplify #(x^2+3x-10)/(x^2+x-20)#? Algebra Rational Equations and Functions Division of Polynomials 1 Answer LM Mar 9, 2018 #(x-2)/(x-4)# Explanation: #-2 + 5 = 3# #-2 * 5 = -10# #x^2+3x-10 = (x-2)(x+5)# #-4 + 5 = 1# #-4 * 5 = -20# #x^2+x-20 = (x-4)(x+5)# #(x^2+3x-10)/(x^2+x-20) = ((x-2)(x+5))/((x-4)(x+5))# #= ((x-2)cancel((x+5)))/((x-4)cancel((x+5)))# #= (x-2)/(x-4)# Answer link Related questions What is an example of long division of polynomials? How do you do long division of polynomials with remainders? How do you divide #9x^2-16# by #3x+4#? How do you divide #\frac{x^2+2x-5}{x}#? How do you divide #\frac{x^2+3x+6}{x+1}#? How do you divide #\frac{x^4-2x}{8x+24}#? How do you divide: #(4x^2-10x-24)# divide by (2x+3)? How do you divide: #5a^2+6a-9# into #25a^4#? How do you simplify #(3m^22 + 27 mn - 12)/(3m)#? How do you simplify #(25-a^2) / (a^2 +a -30)#? See all questions in Division of Polynomials Impact of this question 3676 views around the world You can reuse this answer Creative Commons License