How do you simplify $(x^2+3x-10)/(x^2+x-20)$ ?

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Answer 1 · 2018-03-09T22:26:42

$(x-2)/(x-4)$

$-2 + 5 = 3$
$-2 * 5 = -10$

$x^2+3x-10 = (x-2)(x+5)$

$-4 + 5 = 1$
$-4 * 5 = -20$

$x^2+x-20 = (x-4)(x+5)$

$(x^2+3x-10)/(x^2+x-20) = ((x-2)(x+5))/((x-4)(x+5))$

$= ((x-2)cancel((x+5)))/((x-4)cancel((x+5)))$

$= (x-2)/(x-4)$

How do you simplify (x^2+3x-10)/(x^2+x-20)(x^2+3x-10)/(x^2+x-20)?