How do you simplify #(x^2+3x-10)/(x^2+x-20)#?

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Answer 1 · 2018-03-09T22:26:42

#(x-2)/(x-4)#

#-2 + 5 = 3#
#-2 * 5 = -10#

#x^2+3x-10 = (x-2)(x+5)#

#-4 + 5 = 1#
#-4 * 5 = -20#

#x^2+x-20 = (x-4)(x+5)#

#(x^2+3x-10)/(x^2+x-20) = ((x-2)(x+5))/((x-4)(x+5))#

#= ((x-2)cancel((x+5)))/((x-4)cancel((x+5)))#

#= (x-2)/(x-4)#