How do you simplify ${(x^{\sqrt{5}})}^{\sqrt{3}}$ $(x^sqrt5)^sqrt3$ ?

Question

1666 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-04-13T04:32:10

$\Rightarrow x^{\sqrt{15}}$ $=>x^sqrt15$

According to theory of indices,

${(a^{m})}^{n} = a^{m n}$ $(a^m)^n = a ^(mn)$

$Given {(x^{\sqrt{5}})}^{\sqrt{3}} = {(x)}^{\sqrt{5} \cdot \sqrt{3}}$ $"Given " (x^sqrt5)^(sqrt3) = (x)^(sqrt5 * sqrt3)$

$\Rightarrow x^{\sqrt{15}}$ $=>x^sqrt15$

How do you simplify (x√5)√3(x^sqrt5)^sqrt3?