How do you simplify $\frac{x}{x^{2} - 4} - \frac{2}{x - 2}$ $x/ (x^2 - 4) - 2/(x - 2)$ ?

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How do you simplify $\frac{x}{x^{2} - 4} - \frac{2}{x - 2}$ $x/ (x^2 - 4) - 2/(x - 2)$ ?

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Answer 1 · 2016-07-06T03:30:40

= $\frac{- 1 (x + 4)}{(x - 2) (x + 2)}$ $(-1(x +4))/((x-2)(x+2))$

Explanation:

$\frac{x}{x^{2} - 4} - \frac{2}{x - 2}$ $x/(x^2 - 4) - 2/(x-2)$ can be written as

= $\frac{x}{x^{2} - 2^{2}} - \frac{2}{x - 2}$ $x/(x^2 - 2^2) - 2/(x-2)$

= $\frac{x}{(x - 2) (x + 2)} - \frac{2 (x + 2)}{(x - 2) (x + 2)}$ $x/((x - 2)(x+2)) - (2(x+2))/((x-2)(x+2))$

= $\frac{x - 2 (x + 2)}{(x - 2) (x + 2)}$ $(x - 2(x+2))/((x-2)(x+2))$

= $\frac{x - 2 x - 4}{(x - 2) (x + 2)}$ $(x - 2x - 4)/((x-2)(x+2))$

= $\frac{- x - 4}{(x - 2) (x + 2)}$ $(-x - 4)/((x-2)(x+2))$

= $\frac{- 1 (x + 4)}{(x - 2) (x + 2)}$ $(-1(x +4))/((x-2)(x+2))$

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How do you simplify $\frac{x}{x^{2} - 4} - \frac{2}{x - 2}$ $x/ (x^2 - 4) - 2/(x - 2)$ ?

1 Answer

Explanation:

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How do you simplify $\frac{x}{x^{2} - 4} - \frac{2}{x - 2}$ $x/ (x^2 - 4) - 2/(x - 2)$ ?