How do you simplify $(y²-25) / (3y-7)$ ?

Question

1626 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-07T09:01:48

$(y^2-25)/(3y-7)=((y+5)(y-5))/(3y-7)$

$(y^2-25)/(3y-7)$

Rewrite $25$ as $5^2$ .

$(y^2-5^2)/(3y-7)$

$(y^2-5^2)$ is an example of the difference of squares, $a^2-b^2=(a+b)(a-b)$ , where $a=y and b=5$ .

$((y+5)(y-5))/(3y-7)$

How do you simplify (y²-25) / (3y-7) (y²-25) / (3y-7)?