How do you simplify #y/(2y)+ (y+2)/y#?

Question

2490 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-14T07:31:49

#y/[2y] + [y+2]/y#

#=[y+2(y+2)]/[2y]#

#=[y+2y+4]/[2y]#

#=[3y+4]/[2y]#

Answer 2 · 2018-06-14T07:33:37

#\frac{3y+4}{2y}#

If you multiply and divide by #2# the second fraction we get

#\frac{y}{2y}+\frac{2(y+2)}{2y} = \frac{y+2(y+2)}{2y} = \frac{y+2y+4}{2y}=\frac{3y+4}{2y}#

If you prefer, you can break the fraction in two fraction by writing

#\frac{3y+4}{2y} = \frac{3cancel(y)}{2cancel(y)}+\frac{cancel(4)^2}{cancel(2)y} = \frac{3}[2}+\frac{2}{y}#.

It depends on your idea of "simplifying", as far as I know there is no standard definition for that term. Let me know if I'm wrong!